1.

A thick metallic cylindrical rod which is to be cut when placed between th jasws of a 'vice' the handle to roated though 4xx360^(@), if the distance moved by the movable jaws is 0.5 cm per rotation then calculate the radius of the rod. (Assume that initially th jawsare in contact with each other)

Answer»

Solution : From the question it is clear that the handle was rotated through '4' rotations (N) .
`:. n=4`
The distance moved by the movable jaw per rotation `=0.5cm`
`:.` TOTAL distance moved bythe jaw `=4 xx0.5cm 2cm`
`:.` The DIAMETER of the rod = distance between JAWS when the rod is placedbetween them
`d=2m`
`rArr 2r=2 cm rArrr=1`
`:.` Radius of the rod =1 cm


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