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A thick metallic cylindrical rod which is to be cut when placed between th jasws of a 'vice' the handle to roated though 4xx360^(@), if the distance moved by the movable jaws is 0.5 cm per rotation then calculate the radius of the rod. (Assume that initially th jawsare in contact with each other) |
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Answer» Solution : From the question it is clear that the handle was rotated through '4' rotations (N) . `:. n=4` The distance moved by the movable jaw per rotation `=0.5cm` `:.` TOTAL distance moved bythe jaw `=4 xx0.5cm 2cm` `:.` The DIAMETER of the rod = distance between JAWS when the rod is placedbetween them `d=2m` `rArr 2r=2 cm rArrr=1` `:.` Radius of the rod =1 cm |
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