1.

A thin circular ring of mass m and r is rotating about its axis with a constant angular velocity omega. Two objects, each of mass m are attached gently to the opposite ends of a diameter of the ring wheel now rotates with an angular velocity :

Answer»

`OMEGAM//(M+m)`
`omega(M-2m)//(M+2m)`
`omegaM//(M+2m)`
`omega(M+2m)//M`

SOLUTION :`I_(1)omega_(1)=I_(2)omega_(2)impliesMr^(2)omega=(Mr^(2)+mr^(2)+mr^(2))omega_(2)`
`omega_(2)=(MOMEGA)/(M+2m)`


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