1.

A thin circular ring of mass M and radius r is rotating about its axis with a constant angular velocity omega. Two objects each of mass m are attached gently to the opposite ends of a diameter of the ring. The ring will now rotate with an angular velocity

Answer»

`(omega(M-2M))/M`
`(OMEGAM)/(M+2m)`
`(omega(M-2M))/(M+2m)`
`(omegaM)/(M+m)`

Solution :L = I`omega` = constant (No EXTERNAL torque is acting) `(M + 2m )R^(2)omega. = Mr^(2)omega`
`omega.=(Mr^(2)omega)/((M+2m)r^(2))=(omegaM)/(M+2m)`


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