1.

A thin circular ring of mass Mand radius r is rotating about its axis with a constant angular velocity omega. Four objects each of mass m, are kept gently to the opposite ends of two perpendicular diameters of the ring. The angular velocity of the ring will be

Answer»

`(Momega)/(4m)`
`(Momega)/(M+4m)`
`((M+4m)omega)/M`
`((M-4m)omega)/(M+4m)`

SOLUTION :ACCORDING to conservation of ANGULAR momentum,
`L=Iomega`= CONSTANT. Therefore, `I_(2)omega_(2) = I_(1)omega_(1)`
or `omega_(2)=(I_(1)omega_(1))/(I_(2))=(Mk^(2)omega)/((M+4m)k^(2))=(Momega)/(M+4m)`


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