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A thin film is illuminated by wavelength 600 nm in free space at nearly normal incidence. Calculate the minimum thickness of a thin film (mu = 3/2 ) that results in constructive interference in the reflected light. |
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Answer» Solution :For constructive INTERFERENCE `2MU t = (2N + 1)lamda/2` n=0,1,2, ..... For n=0, 2 `(3/2) t = 600/2 , t= 100nm` |
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