1.

A thin hollow cylinder open at both ends (i) Slides without rotating (ii) Rolls without slipping, with the same speed. The ratio of kinetic energies in the two cases is

Answer»

`1:1`
`4:1`
`1:2`
`2:1`

Solution :TRANSLATIONAL K.E. =`1/2mv^(2)`
K.E. of rolling body= K.E. of translation+ K.E. of rotation
`E=1/2mv^(2)+1/2Iomega^(2)=1/2mv^(2)+1/2mR^(2).OMEGA^(2)`
`E=1/2mv^(2)+1/2mv^(2)=mv^(2)`
`therefore("Translation K.E.")/(.TOTAL K.E.")=1/2.(mv^(2))/(mv^(2))=1/2`


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