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A thin prism is made of a material having refractive indices 1.61 and 1.65 for red and violet light. The dispersive power of the material is 0.07. It is found that a beam of yellow light passing through the prism suffers a minimum deviation of 4.0^@ in favourable conditions. Calculate the angle of the prism. |
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Answer» Solution :Given that : `mu_r=1.61` `mu_v=1.65` `omega=0.07 and delta_y=4^@` Now `w=(mu_v-mu_r)/(mu_y-1)` `=0.07=(1.65-1.61)/(mu_y-1)` `mu_y-1=0.04/0.07=4/7` Again `delta=(mu-1)A` `RARR A=delta_y/(mu_y-1)=4/(4/7) =7` |
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