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A thin rod of mass `M` and length `L` is bent into a semicircle as shown in diagram. What is a gravitational force on a particle with mass `m` at the centre of curvature?A. `(4pi^(2)GMm)/(L^(2))`B. `(GMm)/(4pi^(2)L^(2))`C. `(2piGMm)/(L^(2))`D. zero |
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Answer» Correct Answer - D Field produced by circular rod at its centre is zero. Hence no force is acting on the particle placed at the centre. |
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