1.

A thin rod of mass `M` and length `L` is bent into a semicircle as shown in diagram. What is a gravitational force on a particle with mass `m` at the centre of curvature?A. `(4pi^(2)GMm)/(L^(2))`B. `(GMm)/(4pi^(2)L^(2))`C. `(2piGMm)/(L^(2))`D. zero

Answer» Correct Answer - D
Field produced by circular rod at its centre is zero. Hence no force is acting on the particle placed at the centre.


Discussion

No Comment Found

Related InterviewSolutions