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A thin sheet of a transparent material (mu= 1.60) is placed in the path of one of the interfering beams in a YDSE using sodium light, lambda= 5890 dotA. The central fringe shifts to a position originally occupied by the 12th bright fringe. Calculate the thickness of the sheet. |
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Answer» Solution :`triangle x= (mu-1)t= n lambda` It is GIVEN that `mu= 1.60,n= 12, lambda= 5890 dotA` `THEREFORE t= (12XX 5890 xx 10^(-10))/(1.60-1)= 1.18xx 10^(-5)m = 12 mu m`. |
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