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A thin spherical soap bubble has surface tension S . It's surface is charged with charge Q, its's volume is V it is found that when Q^(2)=npi varepsilon_(0) SV the excees pressure inside the bubble becomes zero find n. |
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Answer» `sigma=Q/(4pir^(2))` ……(2) `sigma^(2)/(2in_(0))+p-p_(0)=(4S)/r` …..(3) `p-p_(0)=0` ….(4) `Rightarrow1/(2 in _(0)).Q^(2)/(16pi^(2)r^(4))=(4s)/r` `RIGHTARROW 1/(2 in_(0)) . (npi in_(0)s)/(16pi^(2)r^(3)). 4/3 pir^(3)=4s` `n=96`
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