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A thin string is held at one end and oscillaes vertically so that, y(x=0,0) = 8 sin dem Neglect the gravirational force. The string 's linear was density is 0.2 Kg/m and its tension is in the string passes through but filled with I kg : Due tofrietion to the heat The heat transfer efficiency is 50%. Calentate how much time passes before the temperature of the bath rises by one degree kelvin. |
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Answer» Solution :`v=sqrt((T)/(mu))=sqrt((1)/(0.2))=2.236m//s` further `rhoS=mu=0.2 kg//m` Te average power over a period is `P=(1)/(2)(rhoS) omega^(2)A^(2)v` Substituting the values, we have`P=2.29xx10^(-2)J//s` Now LET, it takes t SECOND to raise the temperature of 1 kg water by ONE degree kelvin. Then `Pt=ms DELTAT` Here S= specific heat of water `=4.2xx10^(3)J//kg-K` `:.t=(msDeltat)/(P)=((1)(4.2xx10^(3))(1))/(1.145xx10^(-2))~~4.2` DAY |
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