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A thin symmettrical double convex lens of refractive index mu_(2)-1.5 is placed between a medium of refractiv eindex mu_(1)=1.4 to the left and another medium of refractive index mu_(3)=1.6 to the right.Then the system behaves as |
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Answer» a convex LENS For parallel beam of light, `(-mu_(1))/(u)+(mu_(2))/(V)=(mu_(2)-1)/(R )` `rArr -(1.4)/(0oo)+(1.5)/(V)=(1.5-1.4)/(R )rArrV=15R` For second refraction surface, `-(mu_(2))/(1.5r)+(mu_(3))/(V)=(mu_(2))/®` `rArr -(1.5)/(15R)+(1.6)/(V)=(1.6-1.5)/(R)rArrV'=oo` Hence ,the combination behaves as glass plate |
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