A thin uniform equilateral plate rests in a vertical plane with one of its vertex A on a rough horizontal floor and another vertex B on a smooth vertical wall. If the coefficient of friction mu = 1/(sqrt3), then the least angle theta its base AB can make with the horizontal surface is

A thin uniform equilateral plate rests in a vertical plane with one of

1.	A thin uniform equilateral plate rests in a vertical plane with one of its vertex A on a rough horizontal floor and another vertex B on a smooth vertical wall. If the coefficient of friction mu = 1/(sqrt3), then the least angle theta its base AB can make with the horizontal surface is
Answer» `theta = COT^(-1) [mu + 1/(sqrt3)]` `theta = TAN^(-1) [mu + 1/(sqrt3)]` `theta = tan^(-1) [2MU + 1/(sqrt3)]` `theta = cot^(-1) [2mu + 1/(sqrt3)]` ANSWER :D

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A thin uniform equilateral plate rests in a vertical plane with one of its vertex A on a rough horizontal floor and another vertex B on a smooth vertical wall. If the coefficient of friction mu = 1/(sqrt3), then the least angle theta its base AB can make with the horizontal surface is

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