1.

A thin uniform rod of length 2l is acted upon a constant torque. The angular velocity changes from zero to omega in time t. The value of torque is :

Answer»

`(ML^(2)OMEGA)/(t)`
`(ml^(2)omega)/(12T)`
`(ml^(2)omega)/(3t)`
`(2ml^(2)omega)/(t)`

Solution :`I=(1)/(12)M(2L)^(2)=(1)/(3)Ml^(2)`
`alpha=(omega-0)/(t)=(omega)/(t)`
Now `tau=Ixxalpha=(1)/(3)(Ml^(2)omega)/(t)`


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