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A thin uniform rod of length l is pivoted at its upper end. It is free to swing in a vertical plane. Its time period for oscillation of small amplitude isA. `2pisqrt((l)/(g))`B. `2pisqrt((2l)/(3g))`C. `2pisqrt((3l)/(2g))`D. `2pisqrt((l)/(3g))` |
Answer» Correct Answer - B (b) `T=2pisqrt((I)/(mgl//2))=2pisqrt(((ml^(2)//3))/((mgl//2)))( because I_("rod")=(ml^(2))/(3))=2pisqrt((2l)/(3g))` |
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