1.

(a) Three resistor 1Omega ,2Omega, and 3Omega are combined in series. What is the total resistance of the ombination ? (b) If the combination is connected to a battery of emf 12 V and negligible internal resistance, obtain the potential drop across each resistor.

Answer»

Solution :
CURRENT PASSING through battery in above loop,
`I =(epsilon)/(R_(s)+ R) = (epsilon)/(R_(s)) "" (because" Here, r = " 0 )`
`= (12)/(6)`
`therefore I = 2 A `
Voltages across `R_(1), R_(2) , R_(3)` are respectively,
`therefore V_(1) = IR_(1) = 2 xx 1= 2 ` V
`therefore V_(2) = IR_(2) = 2 xx 2 = 4 `V
`therefore V_(3) = IR_(3 ) = 2 xx 3 = 6` V


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