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(a) Three resistors 3Omega, 4Omega, and 12Omega are connected in parallel. What is the effective resistance of the combination? (b) If the combination is connected to a battery of emf 6V and internal resistance 0.5Omega, find the current drawn from the battery and terminal potential difference across the battery. |
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Answer» Solution :Let `R_(1)= 3OMEGA, R_(2)= 4Omega " &" R_(3)=12Omega` are three resistances of the resistors. Effective resistance in parallel `(1)/(R_(P))= (1)/(R_(1)) + (1)/(R_(2)) + (1)/(R_(3))` `(1)/(R_(P))= (1)/(3) + (1)/(4) + (1)/(12)= (96)/(144)` `R_(P)= 1.5Omega` Current DRAWN `I= (E )/(R + r) = (6)/(1.5 + 0.5)= 3A` `V= IR_(P) = 3 Omega xx 1.5A= 4.5V` |
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