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A tiny particle of mass4 mugis kept over a large horizontal sheet of charge density4 xx 10 ^(-6)Cm ^(-1)What charge should be given to the particle so that if released it does not fall down?

Answer»

Solution :Let charge q be GIVEN to the particle. As particle close not fall, hence downward weight of particle mg = upward force due to electric field of charged plate ` q_E =q . (SIGMA)/( 2 in _0) `
` therefore "" q= ( 2 mg in_0)/( sigma ) `
Here , m ` mug= 5 XX 10 ^(-6) g = 5 xx 10 ^(-9) kg , sigma= 4 xx 10 ^(-6)C m^(-1) `
` therefore"" q= ( 2xx 5 xx 10 ^(-9)xx 9.81 xx 8.85 xx 10 ^(-12)) /( 4 xx 10 ^(-6)) = 2.17 xx 10 ^(-13)C . `


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