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A toroid has a core (non-ferromagnetic) of inner radius 25 cm and outer radius 26 cm, around which 3500 turns of a wire are found. If the current in the wire is 11 A, what is the magnetic field (i) outside the toroid, (ii) inside the core of the toroid, and (iii) in the empty space surrounded by the toroid. |
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Answer» Solution :As per DATA GIVEN, MEAN radius of toroid `R = (25 + 26)/(2) = 25.5 cm = 0.255 m` Number of turns per unit length, `n = N/(2 pi R) = (350)/((2 pi) xx (0.255)) m^(-1)` (i) Magnetic field outside the toroid = 0 (ii) Magnetic field inside the core is `B = mu_0 I = (4 pi xx 10^(-7) xx 350 xx 11)/(2pi xx (0.255)) = 3.0 xx 10^(-2) T` (iii) Magnetic field in the empty space surrounded by the toroid is zero. |
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