1.

A toroid has a mean radius R equal to 20//pi cm, and a total of 400 turns of wire carrying a current of 2.0 A. An aluminium ring at temperature 280 K inside the toroid provides the core. If the magnetisation I is 4.8 xx 10^(-2) A m^(-1), then, choose the correct option(s).

Answer»

MAGNETIC intensity in the core is `1000 A m^(-1)`
Susceptibility of the aluminium at TEMPERATURE `280 K is 2.4 xx 10^(-5)`.
If the temperature of the aluminium ring is raised 10 320 K, then the magnetization will be `4.2 xx 10^(-2) Am^(-1)`.
Susceptibility of aluminium at temperature 320 K is `2.1 xx 10^(-5)`

Solution :The NUMBER of turns per uni" length of the toroid is
`n = (400)/(2piR)`
The magnetic intensity H in the core is
`H = ni = (400xx 2.0A)/(2pi20/rxx10^(-2)m)=2000Am^(-1)`
The susceptibility is
`X = I/H = (4.8xx10^(-2)Am^(-1))/(2000Am^(-1))=2.4xx10^(-5)`
The susceptibility X of a paramagncrie substance VARIES with absolute temperature as X = c/T,
`therefore X_(2)//X_(1) = T_(1)//T_(2)`
The susceptibility of aluminium at temperature 320 K is. therefore,
`X_(2) = (280)/(320) xx 2.4 xx 10^(-5) = 2.1 xx 10^(-5)`
Thus the magnetisation at 320 K is
`I = XH -= 2.1 xx 10^(-5) xx 2000 Am^(-1) = 4.2 xx 10^(-2) Am^(-1)`


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