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A toroid of 5000 turns carries a current of 15A. Find the magnetic flux density inside the toroid at a point 25 cm from the centre of the toroidal circle. |
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Answer» SOLUTION :Magnetic field B INSIDE a toroid: `B=mu_@/(2pi)xx(Ni)/r` `(2XX10^(-7)xx5000xx15)/(25xx10^(-2))=0.06T`. |
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