InterviewSolution
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InterviewSolution
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A toroid of non ferromagnetic has core of inner radius 25cm and outer radius 26cm. it has 3500 turns & carries a current of 1JA, then find the magnetic field at a point i) In the internal cavity of toroid ii) At the midpoint of the windings iii) At a point which is at a distance of 30cm from the centre of toroid |
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Answer» Solution :i) B = 0 ii) `B=(mu_(0))/(2pi)(ni)/r=2xx10^(-7)xx(3500xx11)/(51xx10^(-2))xx2` `=88/3xx10^(-3)=29.3xx10^(-3)T` III) B = 0. Based on MAGNETISM for SOLENOID and toroid |
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