A total charge of 5 muC is distributed uniformly on the surface of the thin walled semispherical cup. If the electric field strength at the centre of the hemisphere is 9xx10^(8) NC^(-1), then the radius of the cup is (1/(4pi epsi_(0))=9xx10^(9) N-m^(2) C^(-2))

A total charge of 5 muC is distributed uniformly on the surface of the

1.	A total charge of 5 muC is distributed uniformly on the surface of the thin walled semispherical cup. If the electric field strength at the centre of the hemisphere is 9xx10^(8) NC^(-1), then the radius of the cup is (1/(4pi epsi_(0))=9xx10^(9) N-m^(2) C^(-2))
Answer» 5 mm 10 mm 5 cm 10 cm Answer :A

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A total charge of 5 muC is distributed uniformly on the surface of the thin walled semispherical cup. If the electric field strength at the centre of the hemisphere is 9xx10^(8) NC^(-1), then the radius of the cup is (1/(4pi epsi_(0))=9xx10^(9) N-m^(2) C^(-2))

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