1.

A tower subtends an angle at a point A in the plane of its base and the angle of depression of the foot of the tower at a point b metres just above A is . Prove that the height of tower is btan cot .​

Answer» CD=btanαcotβ [ Hence proved ]Step-by-step explanation:Here, CD is the height of the tower.In △ABC,tanβ= ACAB ⇒ tanβ= ACb ∴ AC= tanβb ∴ AC=bcotβ ------ ( 1 )In △ACD,tanα= ACCD ⇒ CD=tanα×AC⇒ CD=tanα×bcotβ [ From ( 1 ) ]∴ CD=btanαcotβ [ Hence proved ]HOPE THIS HELPS OUT TO UPLS MARK ME AS BRAINLIST


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