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A Train Covers A Distance In 50 Min, If It Runs At A Speed Of 48 Kmph On An Average. The Speed At Which The Train Must Run To Reduce The Time Of Journey To 40 Min Will Be? |
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Answer»
Speed = 48 mph Distance = S×T=48×5/6=40 KM Time = 40/60 hr NEW speed = 40×3/2=60 kmph. Time = 50/60=5/6 hr Speed = 48 mph Distance = S×T=48×5/6=40 km Time = 40/60 hr New speed = 40×3/2=60 kmph. |
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