1.

A Train Covers A Distance In 50 Min, If It Runs At A Speed Of 48 Kmph On An Average. The Speed At Which The Train Must Run To Reduce The Time Of Journey To 40 Min Will Be?

Answer»

TIME = 50/60=5/6 HR

Speed = 48 mph

Distance = S×T=48×5/6=40 KM

Time = 40/60 hr

NEW speed = 40×3/2=60 kmph.

Time = 50/60=5/6 hr

Speed = 48 mph

Distance = S×T=48×5/6=40 km

Time = 40/60 hr

New speed = 40×3/2=60 kmph.



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