A Train Crosses A Post In 1515 Seconds And A Platform 100100 Metre Lo

1.	A Train Crosses A Post In 1515 Seconds And A Platform 100100 Metre Long In 2525 Seconds. Its Length Is?
Answer» The TRAIN can cover a distance equal to its length in 1515 SECONDS. The train can cover (a distance equal to its length + 100100 METRE) in 2525 seconds. Therefore, it can be concluded that the train can travel 100100 metre in (25−15)=10 seconds and therefore its SPEED is 100/10=10 m/s Hence, length of the train =10×15=150 metre. The train can cover a distance equal to its length in 1515 seconds. The train can cover (a distance equal to its length + 100100 metre) in 2525 seconds. Therefore, it can be concluded that the train can travel 100100 metre in (25−15)=10 seconds and therefore its speed is 100/10=10 m/s Hence, length of the train =10×15=150 metre.

A Train Crosses A Post In 1515 Seconds And A Platform 100100 Metre Long In 2525 Seconds. Its Length Is?

Answer»

The TRAIN can cover a distance equal to its length in 1515 SECONDS.

The train can cover (a distance equal to its length + 100100 METRE) in 2525 seconds.

Therefore, it can be concluded that the train can travel 100100 metre in (25−15)=10 seconds and therefore its SPEED is 100/10=10 m/s

Hence, length of the train =10×15=150 metre.

The train can cover a distance equal to its length in 1515 seconds.

The train can cover (a distance equal to its length + 100100 metre) in 2525 seconds.

Therefore, it can be concluded that the train can travel 100100 metre in (25−15)=10 seconds and therefore its speed is 100/10=10 m/s

Hence, length of the train =10×15=150 metre.

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