1.

A train is moving slowly on a straight track with a constant speed of 2" m s"^(-1) . A passengers in the train starts walking at a stready speed of 2" m s"^(-1) to the back of the train in the opposite direction of the motion of the train. So to an observer standing on the platform directly in front of that passenger, the velocity of the passenger appears to be

Answer»

2 `ms^(-1)` in the opposite DIRECTION of the train
zero
4`ms^(-1)`
2 `ms^(-1)`

Solution :For an OBSERVER standing on the platform net velocity of passenger will be zero becouse 2+(-2)=0.


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