1.

A train is moving with a speed of 54 km/h. A monkey is running on the roof of a train against its motion with a speed of 5 ms. w.ut the train. The velocity of the monkey as observed by a man on the ground is :

Answer»

`20 ms^(-1)`
`15ms^(-1)`
`10ms^(-1)`
`5ms^(-1)`

Solution :`v_t=54km//h`=15 m/s,
vel. Of MONKEY w.r.t to train `v_(m-t)=-5m//s^(-1)`
`impliesV_(m)-v_(t)=-5 IMPLIES v_(m)=+10 m//s`
`:. V_(m,obs)=v_(m)-v_(obs)=10-0=10 m//s`


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