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A train is moving with a uniform speed of 33 m/s and an observer is approaching the train with the same speed. If the train blows a whistle of frequency 1000 Hz and the velocity of sound is 333 m/s, then the apparent frequency of the sound that the observer hears is |
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Answer» 1220 HZ `u =((v+v_(0))/(v-v_(0)))v_(0)` Here, `v_(0) = 1000 Hz, v_(0) = v_(s) = 33 MS^(-1)` `v = 333 ms^(-1), v=?` `v=((333 + 33)/(333-33)) xx 1000 = 366/300 xx 1000 = 1200` Hz |
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