A train is travelling at vm//s along a level straight track Very near and parallel to the track is a wall On the wall a naughty boy has drawn a straight line that slopes upward at a 37^(@) angle with the horizontal A passanger in the train is observing the line out of window (0.90 m high 1.8 wide as shown in figure) The line first appears at window corner A and finally disappears at window corner B if it takes 0.4 sec between appearance at A and disappearance of the line at B what is the value of v (in cm//s)?

A train is travelling at vm//s along a level straight track Very near

1.	A train is travelling at vm//s along a level straight track Very near and parallel to the track is a wall On the wall a naughty boy has drawn a straight line that slopes upward at a 37^(@) angle with the horizontal A passanger in the train is observing the line out of window (0.90 m high 1.8 wide as shown in figure) The line first appears at window corner A and finally disappears at window corner B if it takes 0.4 sec between appearance at A and disappearance of the line at B what is the value of v (in cm//s)?
Answer» Solution : `H/(vt-l)=tan 37^(@)` Rightarrow V=`h(+l)/((tan 37^(@)/t)) = 7.5 m//s =750 cm//s]`

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