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A train leaves Pune at 7 :30 am and reaches Mumbai at 11 : 30 am. Another train leaves Mumbai at 9 : 30 am and reaches Pune at 1 : 00 pm. Assuming that the two trains at constant speeds, at what time do the two trains cross each other-A. `10 : 20am`B. `11:30am`C. `10:26am`D. Data not sufficinet |
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Answer» Correct Answer - B First train from Pune to Mumbai takes 4hrs. Second train from Mumbai to Pune takes 3.5hrs. Speed of train from Pune to Mumbai is `V_(1)=(d)/(4)` Speed of train from Mumbai to Pune is `V_(2)=(d)/(3.5)` Distance traveled by first train till 9:30 is `x=(d)/(4)xx2=(d)/(2)` Say now both trains meet after time from 9:30 `(x)/(d//4)=((d)/(2)-xx)/((d)/(3.5))implies(4x)/(d)=(3.5)/(2)-(3.5x)/(d)implies(7.5x)/(d)=(3.5)/(2)implies15xx=3.5dimplies30xx=7d` time taken by first train 9:30 is `(4x)/(d)=4((7)/(30))` `=(14)/(15)` 56min Then both train meet at 9:30+56min =10:26am |
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