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A train passes a bridge 220m long in 30 secs and a station 325 m long in 39 secs. Find the length of the train and also it's speed |
| Answer» GIVEN s = t + 220/30 ... (i) and s = t + 325/39 ... (II) Solving (i) and (ii), we get 39(t + 220) = 30(t + 325) 39T + 8580 = 30t + 9750 9t = 1170 t = 130 m Put in (i), we get Speed = 130 + 220/30 = 350/30 = 11.66 m/sec S = 3600 × 11.66/1000Step-by-step explanation: | |