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A train takes f s to perform a journey. It travels for (t)/(n) s with uniform acceleration, then for (n -3) (t)/(n) with uniform spced v and finally it comes to rest with unifom retardation. The average of the speed of the train is |
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Answer» `(3n-2) (nu)/(2N)`  Displacement = AREA under `nu-t` graph `=(1)/(2)(t+(N-3)(t)/(n))nu` `"Average speed " = ("TOTAL displacement ")/("Total time")` `=((1)/(2)(t+(n-3)(t)/(n))nu)/(t)` `=nu/(2)(1+(n-3)(1)/(n))=(nu)/(2n)(2n-3)` |
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