1.

A transformer has turn ratio 100 : 1. If the secondary coil has 4 amp current, then current in primary coil is

Answer»

4A
0.04 A
0.4 A
400 A

Solution :`(I_(P))/(I_(S))=(N_(S))/(N_(P))` (From THEORY of TRANSFORMER)
`rArr (I_(P))/(4)=(1)/(100)rArr I_(P)=(4)/(100)=0.04 A`


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