A transformer having efficiency of `90%` is working on `200 V` and `3 kW` power supply. If the current in the secondary coil is `6A`, the voltage across the secondary coil and current in the primary coil respectively areA. `300 V,15 A`B. `450 V,15 A`C. `450 V,13.5 A`D. `600 V,15 A`

A transformer having efficiency of `90%` is working on `200 V` and `3

1.	A transformer having efficiency of `90%` is working on `200 V` and `3 kW` power supply. If the current in the secondary coil is `6A`, the voltage across the secondary coil and current in the primary coil respectively areA. `300 V,15 A`B. `450 V,15 A`C. `450 V,13.5 A`D. `600 V,15 A`
Answer» Correct Answer - B We know efficiency `eta=(Output)/(Input)=(V_(s)I_(s))/(V_(p)I_(p))` `implies eta=(V_(s)I_(s))/(V_(p)I_(p)) implies 0.9=(V_(s)(6))/(3xx10^(3))` `implies V_(s)=450 V` As `V_(p)I_(p)=3000` `I_(p)=3000/(V_(p))=3000/200 A=15 A`

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A transformer having efficiency of `90%` is working on `200 V` and `3 kW` power supply. If the current in the secondary coil is `6A`, the voltage across the secondary coil and current in the primary coil respectively areA. `300 V,15 A`B. `450 V,15 A`C. `450 V,13.5 A`D. `600 V,15 A`

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