1.

A transformer with 80% efficiency works at 4 kW and 200 V. If the secondary voltage is 1000 V then the primary and secondary currents are respectively

Answer»

20 A, 3.2 A
20 A, 4 A
4 A, 20 A
3.2 A, 20 A

Solution :Input power is 4 kW (or 4000 W) at 200 V. Hence primary current `I_(p)=(4000)/200 = 20A`
As output VOLTAGE is 1000 V, hence output current `I_(s) = 3200/1000 = 3.2 A`


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