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A transistor has alpha=0.95.If the emitter curent is 10 mA,What is (a) the collector current ,(b)the base current and ( c)gainbeta? |
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Answer» Solution :Here,`ALPHA=0.95,I_E=10mA` (a)`alpha=(I_C)/(I_E)=gtI_C=alphaI_E=0.95xx10=9.5mA` (B)`I_B=I_E-I_C=10-9.5=0.5mA` ( C) `BETA=(alpha)/(1-alpha)=(0.95)/(1-0.95)=(0.95)/(0.05)=19` |
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