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A transistor is connected in CE configuration. The voltage drop across the load resistance (R_C) 3 ks is 6 V. Find the base current. The current gain alpha of the transistor is 0.97 Data : Voltage across the collector load resistance (R_C) = 6 V . alpha= 0.97 :R_C= 3 k Omega |
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Answer» Solution :Thevoltageacross the collectorresistanceis`R_C= I_C R_C= 6V ` hence `I_C=(6 )/(RC )= ( 6 )/( 3 xx 10^3) =2mA` currentgai` beta= (a)/(1-a)= ( 0.97 )/( 1-0.97 ) = 32.33` ` thereforeI_B= (I_C )/(beta) = ( 2 xx 10^(-3))/( 32.33 )= 61.86mu A` |
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