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A transistor oscillator using a resonant circuit with an inductor L (of negligible resistance and a capacitor C in series produce oscillation of frequency f. If L is doubled and C is changed to 4C, then what will be the resonance frequency ? |
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Answer» `f/(2SQRT2)` `THEREFORE 2pif=1/sqrt(LC)` `therefore f=1/(2pisqrt(LC))`…(1) If we double the value of L and value of C is 4 C then, `f_0=1/(2pisqrt(2Lxx4C))` `=1/(2pixx2sqrt2xxsqrt(LC))` `f_0=1/(2sqrt2xx2pisqrt(LC))`..(2) `therefore (f_0)/f = 1/(2sqrt2)` `therefore f_0=f/(2sqrt2)` |
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