1.

A transition metal M can exist in two oxidation states +2 and +3 It forms an oxide whose experiments formula is given by M_xO where xlt1 Then the ratio of metal ions in +3 state to those in +2 states in oxidegiven by :

Answer»

`(1-x)/(1+x)`
1+2x
`1+x/2`
`(2(1-x))/(3x-2)`

SOLUTION :In 1 mole of `M_x O_1`mole of `M^(2+)` ION=y `:.` mole of `M^(3+)` ion =x-y
Applying CHARGE BALANCE, 2y+3(x-y)-2=0 `implies` y=3x-2
`:. M^(3+)/M^(2+)=(x-y)/y=(x-(3x-2))/(3x-2)=((-2x+2))/(3x-2)=(2(1-x))/(3x-2)`


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