1.

A transmitting antenna at the top of the tower has a height 18 m and the height of the receiving antenna is 32m. The maximum distance between them for satisfactory communciation in line of sight mode is (Radius of earth= 6.4xx10^(6)m)

Answer»

15.15km
21.25km
30.45km
35.42km.

Solution :here `h_(t)=18M,h_(R)=32m`,
`R6.4xx10^(6)m=64xx10^(5) m`
The maximum line or sight DISTANCE
`d_(m)=SQRT(2Rh_(T))+sqrt(2Rh_(R))`
`=sqrt(2xx64xx10^(5)xx18)+sqrt(2xx64xx10^(5)xx32)`
`=112xx10^(2)xxsqrt(10) m=35417.5m=35.42km`


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