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A transmitting antenna of height 20 m and the receiving antenna of height h are separated by a distance of 40km for satisfactory communication in line of sight mode. Then the value of h is |
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Answer» 40m where `h_(R)` and `h_(T)` are the heights of receiving and transmitting antenna and r is the RADIUS of the EARTH. `40xx10^(3)=sqrt(2xx6400xx10^(3)XXH)+sqrt(2xx6400xx10^(3)xx20)` `40xx10^(3)=sqrt(2xx6400xx10^(3)xxh)+16xx10^(3)` `h=([(40-16)xx10^(3)]^(2))/(2xx6.4xx10^(6))=45m` |
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