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A transverse periodic wave on a string with a linear mass density of `0.200 kg//m` is described by the following equation `y = 0.05 sin(420t - 21.0 x)` where `x` and `y` are in meters and `t` is in seconds. The tension in the string is equal to :A. `32 N`B. `42 N`C. `66 N`D. `80 N` |
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Answer» Correct Answer - D `V_(omega) = (omega)/(k) = (420)/(21) = 20 :. V = sqrt((T)/(mu)) = 20 rArr T = (20)^(2)mu = 20^(2) xx 0.2 = 80N` |
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