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    				| 1. | A transverse periodic wave on a string with a linear mass density of 0.200 kg/m is described by the following equation `y=0.05 sin (420t-21.0 x)` where x and y are in metres and t is in seconds.The tension in the string is equal to :A. `32 N`B. `42 N`C. `66 N`D. `80 N` | 
| Answer» Correct Answer - D `V_(omega) = (omega)/(k) = (420)/(21) = 20 :. V = sqrt((T)/(mu)) = 20 rArr T = (20)^(2)mu = 20^(2) xx 0.2 = 80N` | |