InterviewSolution
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InterviewSolution
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A transverse sinusoidal wave of amplitude a, wavelength `lambda` and frequency `f` is travelling on a stretched string. The maximum speed of any point in the string is `v//10`, where `v` is the speed of propagation if the wave. If `a = 10^(-3)m` and `v = 10ms^(-1)`, then `lanbda` and `f` are given byA. (a) `lambda = 2pi xx 10^(-2)m`B. (b) `lambda = 10^(-3)m`C. ( c ) `f = 10^(3) Hz//(2pi)`D. (d) `f = 10^(4)Hz` |
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Answer» Correct Answer - A::C (a,c) NOTE : For a transverse sinusoidal wave travelling on a stirng, the maximum velocity is `aomega`. But maximum velocity is `(v)/(10) = (10)/(10) = 1m//s` :. `aomega = 1` rArr `10^(-3) xx 2piv = 1` `v = (1)/(2pi xx 10^(-3)) = (10^(3))/(2pi) Hz` :. `lambda = (v)/(v) = (10)/(10^(3)//2pi) = 2pi xx 10^(-2)m` |
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