1.

A transverse wave is represented by the equation y = y_(0) (2pi)/(lambda)sin (vt - x). For what value of lambda is the particle velocity equal to two times the wave velocity ?

Answer»

`lambda = 2 PI y_(0)`
`lambda = 2 pi y_(0)` /3
`lambda = 2pi y_(0)` /2
`lambda = 2 pi y_(0)`.

Solution :PARTICLE vel. = `(DY)/(DT) = (2 pi)/(lambda) vy_(0)`
Now `(2pi)/(lambda) vy_(0) = 2v`
or `lambda = pi y_(0)`
CORRECT choice is (D).


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