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A transverse wave is represented by the equation y = y sin (2pi)/lambda (vt -x)For what value of lambda , is the maximum particle velocity equal to two times the wave velocity? |
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Answer» `lambda = (pi y_(0))/2` `y =y_(0)sin (2pi)/lambda (vt -X)` Particle VELOCITY `=(DY)/(dt) = y_(0)COS (2pi)/lambda (vt-x) .(2PIV)/lambda` `((dy)/(dt))_("max") = y_(0).(2pi)/lambda v` `therefore y_(0) =(2pi)/lambda v =2 v` or `lambda = pi y_(0)` |
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