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A transverse wave is represented by `y=Asin(omegat-kx)`. For what value of the wavelength is the wave velocity equal to the maximum particle velocity?A. `piy_(0)`B. `2piy_(0)`C. `piy_(0)//2`D. `4piy_(0)` |
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Answer» Correct Answer - A `V_(wave)=omega/k` `V_(particle)=dy/dt=ubrace(y_(0)omega) cos(omegat-kx)` `y_(0)omega=2(omega)/(k)impliesk=(2)/(y_(0))=(2pi)/(lamda)implieslamda=piy_(0)` |
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