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A transverse wave on a string has an amplitude of 0.2 m and a frequency of 175 Hz. Consider a particle of the string at x=0. it begins with a displacement y=0, at t=0, according to equation `y=0.2 sin (kx+-omegat)`. How much time passed between the first two instant when this particle has a displacement of y=0.1 m?A. 1.9 msB. 3.9 msC. 2.4 msD. 0.5 ms |
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Answer» Correct Answer - a `y=(0.2 m) sin [kx+-omegat]` for `x=0, y=0.1 m` `0.1=0.2 sin(omegat)` `impliesomegat=pi//6 or 5pi//6` So, `t_(2)=5pi//6omega` and `T_(1)=pi//6omega` `t_(2)-t_(1)=2pi//3omega=1//3f=1.9 ms` |
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