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A transverse wave propagating along x-axis is represented by y(x,t) = 8.0 sin(0.5 pi - 4pit - pi//4) where x is in metres and t is in seconds. The speed of the wave is |
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Answer» 8 m/s Compare with a standard wave equation, `y =asin((2pix)/lambda -(2pit)/T + PHI)` we GET, `(2pi)/lambda = 0.5 pi` or `lambda =(2pi)/(0.5 pi) = 4M` and `(2pi)/T = 4pi` or `T =(2pi)/(4pi) = 1/2 s` `therefore v = 1//T =2 Hz` Wave velocity, `v= lambda v = 4 xx2 = 8 m//s` |
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